# PCB Heaven

## General Category => Maths, Geometry, Physics and others => Topic started by: jack_in-a_box on September 22, 2008, 20:01:16 PM

Title: How to calculate the angle of each corner on any n-angle with same angles
Post by: jack_in-a_box on September 22, 2008, 20:01:16 PM
It is me again  ;D

i think i like your forum. You gave me the answer before, i am sure you will give me one again.

We have any shape with more than 3 angles. For example a hexagon. All angles and sides are the same. How can i calculate with as simple as can be calculation, the angle of this shape by knowing only the number of sides?
Title: Re: How to calculate the angle of each corner on any n-angle with same angles
Post by: kam on September 25, 2008, 12:04:47 PM
The central angle of a n-gono is always 360/n. You may calculate all other parts from this
Title: Re: How to calculate the angle of each corner on any n-angle with same angles
Post by: Supernova on October 01, 2008, 23:30:27 PM
Simplified:

A triangle from center of the n-gono to 2 near corners, will have in center 360/n degrees. Easy to understand as you actually divide a circle into n arcs.
Each triangle (n triangles total) will have the other 2 corners equal and equal to (180-(360/n))/2

Each angle of the n-gono between it;s sides will be consisted of the angles of 2 triangles, thsu it will be

2 X (180-(360/n))/2 = 180 - 360/n
Title: Re: How to calculate the angle of each corner on any n-angle with same angles
Post by: Mercury on October 02, 2008, 08:30:47 AM
180-360/n

or

(180 (n-2))/n

;D ;D ;D
Title: Re: How to calculate the angle of each corner on any n-angle with same angles
Post by: jack_in-a_box on October 12, 2008, 10:34:21 AM
Thabks for the solution people! Thank you very much
Title: Re: How to calculate the angle of each corner on any n-angle with same angles
Post by: kam on October 12, 2008, 21:45:46 PM
Keep visiting us friend
Title: Re: How to calculate the angle of each corner on any n-angle with same angles
Post by: Supernova on October 14, 2008, 23:10:33 PM
;)